PROGRAM NO.2
OBJECT: Write a program to add two 16 bit hexadecimal numbers with carry.
INSTRUMENT REQUIRED: 8086 Microprocessor Trainer Kit.
PROGRAM:
| MEMORY LOCATION | MACHINE CODE | OPCODE | OPERAND |
| 0208 | B1 00 | MOV | CL,00H |
| 020A | BE 00 02 | MOV | SI,0200H |
| 020D | 8B 04 | MOV | AX,[SI] |
| 020F | 46 | INC | SI |
| 0210 | 46 | INC | SI |
| 0211 | 8B 1C | MOV | BX,[SI] |
| 0213 | 03 C3 | ADD | AX,BX |
| 0215 | 73 02 | JNC L1 | |
| 0217 | FE C1 | INC | CL |
| 0219 | BF 04 02 | L1 : MOV | DI,0204H |
| 021C | 89 05 | MOV | [DI],AX |
| 021E | 47 | INC | DI |
| 021F | 47 | INC | DI |
| 0220 | 89 0D | MOV | [DI],CL |
| 0222 | F4 | HLT |
DESCRIPTION:
To solve the given objective, we have taken two hexadecimal numbers in the memory locations of 0200H and 0203H and added them and stored the result in the memory location of 0204H, we have also stored the carry in the memory location 0206H
To solve the given objective, we have taken the following steps:
- Initialize the counter register CL to 0.
- Move the source index register (SI) pointer to the location of the first number.
- Store the first number in the AX register using SI.
- Double increment the SI pointer to point to the memory location of the second number.
- Store the second number in the BX register using SI.
- Now apply ADD operation to add the numbers in the registers AX and BX and store the result in AX.
- Jump instruction is used that increments the carry counter if there is no carry else increments the carry counter.
- Move the destination index (DI) pointer to point to the memory location where the result is to be stored.
- Move the result from the AX register to the destination using DI.
- Finally increment the DI to point to the location to store the carry bit and move the carry bit to the destination before halting.
INPUT VALUE:
| MEMORY LOCATION | VALUE |
| 0200H | FF |
| 0201H | FF |
| 0202H | FF |
| 0203H | FF |
| 0204H | 00 |
| 0205H | 00 |
| 0206H | 00 |
| 0207H | 00 |
OUTPUT:
| MEMORY LOCATION | VALUE |
| 0204H | FE |
| 0205H | FF |
| 0206H | 01 |
| 0207H | 00 or Return Garbej Value |
RESULT:The addition of the two hexadecimal numbers FFFFh and FFFFh yields FFFEh as the sum and 0001 as the carry.
COMMENTS:
1. MOV SI,0200H: 16 bit data can be moved using immediate addressing . 0200 is moved to source index.
2. ADD AX,BX: Contents in the accumulator and the base register are added.
3. INC SI: The content of a specified 8-bit or 16-bit register or memory location(s) is incremented by one by this instruction.
4. HLT: This instruction stops program execution. The processor stops fetching and executing instructions.
FLOWCHART:
Most Important Question for Exam
1. Eight of the register are known as:
General purpose register
2. The four Index register can be used for:
Arithmatic operation
3. IP Stand for:
Instruction Pointer
4. CS Stand for:
Code Segment
5. DS Stand for:
Deta Segment
6. Which are the segment:
ES:Extra Segment
7. 8088 Microprocessor differs with 8086 Microprocessor in
Data without on the output
8. In 8086 Microprocessor one of the following statements is not true.
Coprocessor is interfaced in MIN mode
9. In 8086 Microprocessor the following has the highest priority among all type interrupts.
NMI
10. BHE of 8086 Microprocessor signla is used to interface the
Odd bank memory
11. The advantage of memory mapped I/O over I/O mapped I/o is.
All the above
12. In 8086 the overflow flag is set when
Signed numbers go out of their range
13. Address line for RST3 is ?
0018H
14. Which Processor structure is pipelined
All x86 Processor
15. Can ROM bes used asstack?
No
16. What does Microprocessor speed depends on?
Clock
17. In 8086, Example for Non maskable interrupts are
Trapb
18. What is meant by Maskable interrupts?
An Interrupt that can be turned off by the programmer
19. RIM is used to check whether,________
The Interrupt is Masked or not
20. What is SIM
Set Interrupt Mask.
21. Why 8085 Processor is called and 8 bit Processor?
Because 8085 Processor has 8 bit ALU.
22. Which stack is used in 8085?
LIFO
23. What are software interrupts?
RST0-7
24. Which interrupt not level sensetive in 8085?
RST7.5 is a raising edge-trigging interrupt.
25. What are level Triggering interrupts?
RST6.5 & RST5.5
26. What is the RST for the TRAP?
RST4.5
27. Which of the following is hardware interrupts?
B & C
28. In 8085 name the 16 bit registers?
B & C
29. The access method used for maganetic tape is ______________
Sequential
30. By Processing we understand ____________________
None of the above
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